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YOU SAID:

when we take the cube root of a prime number it is not an integer because if it were, the original number would not be prime because it would in fact be the third power of some other integer that is maybe one

INTO JAPANESE

素数の立方根を取るとき、整数ではありません。なぜなら、もしそうなら、元の数は実際には他の整数の3乗であるため、素数ではないからです。

BACK INTO ENGLISH

When taking the cube root of a prime number, it is not an integer. Because, if so, the original number is not prime because it is actually the cube of another integer.

INTO JAPANESE

素数の立方根をとるとき、それは整数ではありません。その場合、元の数は実際には別の整数の立方体であるため、素数ではありません。

BACK INTO ENGLISH

When taking the cube root of a prime number, it is not an integer. In that case, the original number is not prime because it is actually a cube of another integer.

INTO JAPANESE

素数の立方根をとるとき、それは整数ではありません。その場合、元の数は実際には別の整数の立方体であるため素数ではありません。

BACK INTO ENGLISH

When taking the cube root of a prime number, it is not an integer. In that case, the original number is not prime because it is actually a cube of another integer.

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02Jul14
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