Translated Labs

YOU SAID:

sin(A + B) = sinA cosB + cosA sinB

INTO JAPANESE

sin(A + B) = sinA cosB + cosA sinB

BACK INTO ENGLISH

sin(A + B) = sinA cosB + cosA sinB

INTO JAPANESE

sin(A + B) = sinA cosB + cosA sinB

BACK INTO ENGLISH

sin(A + B) = sinA cosB + cosA sinB

Equilibrium found!

That's deep, man.

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